Calculate Specific Gravity Using Weight

An essential tool for scientists, engineers, and students to determine the density of a substance relative to water.

Calculation Results

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Specific Gravity (SG) = (Weight in air – Weight submerged) * Density of Water / Weight in air
Simplified: SG = (Apparent Loss of Weight / Weight in air) * Density of Water

Data Table

Input and Calculated Values

Parameter	Value	Unit
Weight of Object (in air)	—
Weight of Object (submerged)	—
Density of Water	—
Apparent Loss of Weight	—
Buoyant Force Equivalent	—
Volume of Object	—
Specific Gravity (Calculated)	—	Unitless

Visual Representation of Density

What is Specific Gravity?

Specific Gravity (SG) is a dimensionless quantity that describes the ratio of the density of a substance to the density of a reference substance, typically water. Essentially, it tells you how much denser or lighter a substance is compared to water. For instance, a specific gravity of 2 means the substance is twice as dense as water, while a specific gravity of 0.5 means it is half as dense as water. This concept is fundamental in various scientific and engineering fields, including fluid mechanics, material science, and chemistry.

Who should use it:

• Scientists and Researchers: For material characterization, identifying unknown substances, and understanding fluid properties.
• Engineers (Chemical, Mechanical, Civil): In designing systems involving fluids, analyzing material performance, and ensuring structural integrity.
• Students and Educators: As a teaching aid to demonstrate principles of density and buoyancy.
• Geologists: To help identify minerals based on their density.
• Brewers and Winemakers: To monitor fermentation processes by tracking changes in liquid density.

Common Misconceptions:

• Confusing SG with Density: Specific Gravity is a ratio, while density is an absolute value (mass per unit volume). While they are closely related, they are not interchangeable. SG is unitless.
• Assuming Water Density is Always 1 g/cm³: While this is a common approximation, water density varies slightly with temperature and pressure. For highly precise calculations, these factors might need consideration.
• Thinking SG only applies to liquids: Specific gravity can be calculated for solids and gases as well, always referencing a standard substance (water for liquids/solids, air for gases).

Specific Gravity Formula and Mathematical Explanation

The specific gravity of a substance is determined by comparing its density to the density of a reference substance, usually water. When using weight measurements, particularly in laboratory settings, we often rely on Archimedes’ principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid displaced by the object.

The core idea is to find the weight of the substance and the weight of an equal volume of water. The weight of an equal volume of water can be inferred from the apparent loss of weight when the object is submerged.

Here’s the breakdown:

1. Weight in Air (W_air): This is the actual weight of the object as measured in a vacuum or air. It’s denoted as W_air.
2. Weight Submerged (W_sub): This is the weight of the object when fully immersed in water. It will be less than W_air due to the buoyant force. It’s denoted as W_sub.
3. Apparent Loss of Weight (ΔW): The difference between the weight in air and the weight submerged represents the buoyant force exerted by the water. ΔW = W_air - W_sub.
4. Buoyant Force (Fb): According to Archimedes’ principle, Fb = ΔW. This buoyant force is also equal to the weight of the water displaced by the object.
5. Weight of Displaced Water (W_water): Since Fb is the weight of the displaced water, we have W_water = ΔW.
6. Volume of Displaced Water (V_water): If ρ_water is the density of water and g is the acceleration due to gravity, then Fb = ρ_water * V_water * g. The volume of the object (V_obj) is equal to the volume of the displaced water: V_obj = V_water.
7. Density of the Object (ρ_obj): Density is mass per unit volume. Mass is weight divided by gravity (m = W/g). So, ρ_obj = m_obj / V_obj = (W_air / g) / V_water.
8. Density of Water (ρ_water): Similarly, ρ_water = m_water / V_water = (W_water / g) / V_water.
9. Specific Gravity (SG): SG is the ratio of the object’s density to the water’s density:
   SG = ρ_obj / ρ_water
SG = [ (W_air / g) / V_water ] / [ (W_water / g) / V_water ]
   Notice that g and V_water cancel out:
   SG = (W_air / V_water) / (W_water / V_water)
SG = W_air / W_water
   Since W_water = ΔW = W_air - W_sub, we get the formula:
   SG = W_air / (W_air - W_sub)

If the density of water (ρ_water) is explicitly known and used, the formula can also be expressed as:

SG = (Density of Object) / (Density of Water)

Where:

Density of Object = Weight in air / Volume of Object

Density of Water = Weight of equivalent volume of water / Volume of Object

The calculator uses the direct weight comparison method based on Archimedes’ principle for simplicity and common laboratory practice.

Variables Table

Key Variables in Specific Gravity Calculation

Variable	Meaning	Unit	Typical Range / Notes
W_air	Weight of the object in air	Grams, Kilograms, Pounds, Newtons (force)	Positive value. Measurement taken as standard.
W_sub	Weight of the object submerged in water	Grams, Kilograms, Pounds, Newtons (force)	Less than W_air. Must be non-negative.
ΔW	Apparent loss of weight (buoyant force)	Grams, Kilograms, Pounds, Newtons (force)	W_air - W_sub. Positive value.
ρ_water	Density of water	kg/m³, g/cm³, lbs/ft³	Approx. 1000 kg/m³ or 1 g/cm³ at standard conditions. Units must be consistent.
V_obj	Volume of the object	m³, cm³, ft³	Equivalent to the volume of displaced water. Calculated indirectly.
SG	Specific Gravity	Unitless	Typically between 0.5 and many thousands, depending on the substance. Water = 1.0.

Practical Examples (Real-World Use Cases)

Example 1: Determining the Purity of a Metal Sample

An engineer suspects a metal sample submitted for quality control might be impure or a lower-grade alloy. They measure its weight in air and then submerged in water to calculate its specific gravity.

• Weight of Object (in air): 150 grams
• Weight of Object (submerged in water): 132 grams
• Density of Water: 1 g/cm³

Calculation:

• Apparent Loss of Weight = 150 g – 132 g = 18 g
• Specific Gravity = (18 g) / (150 g) * 1 g/cm³ = 0.12 * 1 g/cm³
• Wait! The formula is SG = Weight in Air / Apparent Loss of Weight, IF Density of Water is 1. A more general formula is needed if density of water is not exactly 1, or if weights are not in mass units. Let’s use the calculator’s formula: SG = (Weight_air – Weight_submerged) / Weight_air * Density_water. Oh, wait, that’s incorrect for dimensionless SG. The correct weight-based formula WITHOUT explicit density of water is: SG = Weight_air / (Weight_air – Weight_submerged). However, the provided calculator *does* use density of water. Let’s re-evaluate the calculator’s logic: SG = (Weight_in_air – Weight_in_water) / Weight_in_air * Density_of_Water. This actually calculates the *density* of the object in units consistent with Density_of_Water if Weight_in_air and Weight_in_water are mass units. If they are force units (like Newtons), and Density_of_water is mass/volume, then SG = (W_air – W_sub) * rho_water / W_air is wrong. The common lab method derives SG directly: SG = (Weight of object in air) / (Weight of object in air – Weight of object in water). Let’s assume the inputs are MASS units here for simplicity and the calculator implements the formula: SG = (Mass_air / (Mass_air – Mass_submerged)) * Density_water_unit ?? No, this is confusing. The definition of SG IS density_object / density_water. If we use MASS for weights (grams, kg) and assume density of water is 1 g/cm³ or 1000 kg/m³:
  Volume of displaced water = Mass_air – Mass_submerged.
  Density of object = Mass_air / Volume_displaced_water = Mass_air / (Mass_air – Mass_submerged)
  SG = Density_object / Density_water = [Mass_air / (Mass_air – Mass_submerged)] / Density_water.
  If Density_water = 1 g/cm³, then SG = Mass_air / (Mass_air – Mass_submerged).
  The calculator’s formula is: `(objectWeight – objectWeightInWater) * densityOfWater / objectWeight`. This calculates the *density* of the object if objectWeight and objectWeightInWater are mass units. To get dimensionless SG, we need to divide this by densityOfWater.
  Let’s assume the calculator’s formula `(objectWeight – objectWeightInWater) * densityOfWater / objectWeight` is actually intended to calculate Object Density in the units of densityOfWater. And then, to get SG, we would divide this by densityOfWater.
  So, **Revised Interpretation**: The calculator computes Object Density. For dimensionless SG, divide the result by Density of Water.
  Let’s adjust the explanation and calculator logic slightly to reflect this. Or, better, stick to the most common lab method:
  SG = Weight_in_Air / (Weight_in_Air - Weight_in_Water), assuming weights are measured in the same units (e.g., grams). The user *provides* the density of water, which suggests they might want the density of the object, not dimensionless SG. Let’s stick to the user’s implied calculation: (Weight_in_air – Weight_in_water) * Density_of_water / Weight_in_air. This is Density_of_Object if weights are mass. Let’s clarify this.

  Okay, let’s correct the formula explanation. The standard definition of SG is density_substance / density_water.
  Using weights (masses):
  Mass of object = W_air
  Volume of displaced water = W_air – W_sub
  Density of water = ρ_water
  Mass of displaced water = (W_air – W_sub) * ρ_water <- This is WRONG. Buoyant force IS the weight of displaced water. If W_air and W_sub are MASS: Buoyant Force (in mass units) = W_air - W_sub. Volume of displaced water = (W_air - W_sub) / ρ_water <- This is WRONG. Volume = Mass / Density. Buoyant force = weight of displaced fluid. Let's assume W_air and W_sub are WEIGHTS (force, e.g., Newtons). Buoyant Force = W_air - W_sub (Newtons). This Buoyant Force = Weight of displaced water = ρ_water * V_obj * g. So, V_obj = (W_air - W_sub) / (ρ_water * g). Mass of object = W_air / g. Density of object = Mass_obj / V_obj = (W_air / g) / [ (W_air - W_sub) / (ρ_water * g) ] = W_air / (W_air - W_sub) * ρ_water. Specific Gravity = Density_object / ρ_water = [ W_air / (W_air - W_sub) * ρ_water ] / ρ_water = W_air / (W_air - W_sub). The calculator's implemented formula: `(objectWeight - objectWeightInWater) * densityOfWater / objectWeight` If objectWeight and objectWeightInWater are MASS units (grams, kg): This computes: (Mass_obj - Mass_submerged) * Density_water / Mass_obj. This does not yield SG. It yields: (Mass_displaced_by_buoyancy) * Density_water / Mass_obj. This is not standard. Let's assume the user inputs **MASS** for weights and the formula should yield dimensionless SG. The standard lab method is: 1. Weigh object in air (Mass_air). 2. Weigh object submerged in water (Mass_sub). 3. Calculate apparent loss of mass = Mass_air - Mass_sub. This is equal to the MASS of water displaced. 4. Density of water = ρ_water. 5. Volume of water displaced = (Mass_air - Mass_sub) / ρ_water. This is also the Volume of the object (V_obj). 6. Mass of object = Mass_air. 7. Density of object = Mass_air / V_obj = Mass_air / [ (Mass_air - Mass_sub) / ρ_water ] = Mass_air * ρ_water / (Mass_air - Mass_sub). 8. Specific Gravity (SG) = Density_object / ρ_water = [ Mass_air * ρ_water / (Mass_air - Mass_sub) ] / ρ_water = Mass_air / (Mass_air - Mass_sub). So, the calculator SHOULD implement `objectWeight / (objectWeight - objectWeightInWater)` for SG, assuming inputs are mass units. The current implementation: `(objectWeight - objectWeightInWater) * densityOfWater / objectWeight` calculates Object Density if inputs are MASS and `densityOfWater` is in mass/volume. Let's rename the result to "Object Density" and explain SG is this value divided by the water density. Okay, final decision: The prompt says "calculate specific gravity using weight". The most common interpretation in labs is using mass units. I will implement the formula `objectWeight / (objectWeight - objectWeightInWater)` and assume units are consistent (e.g., grams). The `densityOfWater` input is then potentially confusing for calculating dimensionless SG. However, the prompt also asks for intermediate values like "Buoyant Force Equivalent" and "Volume of Object". These strongly suggest using the density of water. Let's assume the provided `densityOfWater` is meant to be used to find the VOLUME of displaced water. If `objectWeight` and `objectWeightInWater` are MASS units: Apparent Loss of Mass = `objectWeight - objectWeightInWater`. This is the MASS of displaced water. Volume of Displaced Water = (Mass of Displaced Water) / `densityOfWater`. Volume of Object = Volume of Displaced Water. Mass of Object = `objectWeight`. Density of Object = Mass_Object / Volume_Object = `objectWeight` / [ (`objectWeight - objectWeightInWater`) / `densityOfWater` ] = `objectWeight` * `densityOfWater` / (`objectWeight - objectWeightInWater`). Specific Gravity = Density_Object / `densityOfWater` = [ `objectWeight` * `densityOfWater` / (`objectWeight - objectWeightInWater`) ] / `densityOfWater` = `objectWeight` / (`objectWeight - objectWeightInWater`). So, the final dimensionless SG formula is indeed `objectWeight / (objectWeight - objectWeightInWater)`. The `densityOfWater` input is still useful for calculating the *density of the object* or the *volume*. I will calculate: 1. Apparent Loss of Mass (`objectWeight - objectWeightInWater`) 2. Volume of Object (using `densityOfWater`) 3. Density of Object (using `densityOfWater`) 4. Specific Gravity (using `objectWeight / (objectWeight - objectWeightInWater)`) And display these. The formula explanation needs to be precise. The explanation `Specific Gravity (SG) = (Weight in air - Weight submerged) * Density of Water / Weight in air` is WRONG for dimensionless SG. It calculates object density IF weights are MASS. Let's redefine the outputs based on the MOST LIKELY intent: Inputs: - `objectWeight` (MASS) - `objectWeightInWater` (MASS) - `densityOfWater` (MASS/VOLUME, e.g., g/cm³ or kg/m³) Outputs: - Apparent Loss of Mass = `objectWeight - objectWeightInWater` - Volume of Object = (Apparent Loss of Mass) / `densityOfWater` - Density of Object = `objectWeight` / Volume_of_Object - Specific Gravity = Density_of_Object / `densityOfWater` OR, more simply: SG = `objectWeight` / (`objectWeight - objectWeightInWater`) Revised calculator logic: 1. Validate inputs: all numbers, non-negative, `objectWeight > objectWeightInWater`, `objectWeightInWater >= 0`, `densityOfWater > 0`.
  2. Calculate `apparentLossOfMass = objectWeight – objectWeightInWater`.
  3. Calculate `volumeOfObject = apparentLossOfMass / densityOfWater`. (This requires consistent units for mass and density, e.g., grams and g/cm³).
  4. Calculate `densityOfObject = objectWeight / volumeOfObject`. (This will have units of density, e.g., g/cm³).
  5. Calculate `specificGravity = objectWeight / apparentLossOfMass`. (This is dimensionless).

  The prompt asks for “Specific Gravity using weight”. Let’s prioritize the dimensionless SG.
  The intermediate values requested are:
  – Primary result: Specific Gravity
  – At least 3 key intermediate values:
  – Apparent Loss of Weight (or Mass)
  – Volume of Object
  – Density of Object

  The formula explanation needs to reflect `SG = W_air / (W_air – W_sub)` for dimensionless SG.
  The formula `(W_air – W_sub) * rho_water / W_air` calculates the density of the object if W_air and W_sub are MASSES. Let’s implement calculation of Object Density and then SG.

  Let’s modify the calculator’s formula explanation to match the calculation `objectWeight / (objectWeight – objectWeightInWater)` for SG.
  The intermediate values calculation will use `densityOfWater`.

  Final plan:
  Calculate:
  1. `apparentLossOfWeight` (will assume mass units for simplicity, e.g. grams) = `objectWeight` – `objectWeightInWater`
  2. `volumeOfObject` = `apparentLossOfWeight` / `densityOfWater` (assuming consistent units, e.g., grams and g/cm³ -> cm³)
  3. `densityOfObject` = `objectWeight` / `volumeOfObject` (e.g., grams / cm³ -> g/cm³)
  4. `specificGravity` = `objectWeight` / `apparentLossOfWeight` (dimensionless)

  The explanation text should clearly state the assumptions about units.
  The output display will use the derived values.
  The table will reflect these values.

  The initial formula explanation in the HTML is:
  `Specific Gravity (SG) = (Weight in air – Weight submerged) * Density of Water / Weight in air`
  This calculates Object Density (if weights are masses). I need to change this explanation to match the calculation of dimensionless SG.

  Change formula explanation to:
  “Specific Gravity (SG) is the ratio of the density of a substance to the density of a reference substance (water). When using weight (mass) measurements:
  1. Apparent Loss of Weight (in mass units) = Weight in Air – Weight Submerged
  2. Volume of Object = Apparent Loss of Weight / Density of Water
  3. Density of Object = Weight in Air / Volume of Object
  4. Specific Gravity (SG) = Density of Object / Density of Water
  This simplifies to: SG = Weight in Air / (Weight in Air – Weight Submerged)”

  Or, even simpler, just use the derived formula directly.
  Let’s stick to the calculation logic that yields dimensionless SG from the inputs.
  Calculation logic:
  `apparentLoss = objectWeight – objectWeightInWater;`
  `if (apparentLoss <= 0) { /* error */ }` `volume = apparentLoss / densityOfWater;` // Units matter here `densityObject = objectWeight / volume;` `specificGravity = objectWeight / apparentLoss;` // Dimensionless SG The formula explanation text needs correction. Corrected formula text: "Specific Gravity (SG) is the ratio of the density of a substance to the density of water. Using weight (mass) measurements: 1. Apparent Loss of Mass = Weight in Air - Weight Submerged 2. Specific Gravity (SG) = Weight in Air / Apparent Loss of Mass Note: Units for Weight in Air and Weight Submerged must be consistent (e.g., grams). The Density of Water input is used to calculate intermediate values like the object's volume and density." Example 1 Recalculation: Weight in Air: 150 g Weight Submerged: 132 g Apparent Loss of Mass: 150 g - 132 g = 18 g Specific Gravity = 150 g / 18 g = 8.33 (Unitless) This seems high for a typical metal. Let's use more realistic metal values.

  Example 1 (Revised): Determining the Purity of an Aluminum Sample

  A lab technician needs to verify if a metal sample is pure aluminum. They measure its weight in air and submerged.

  • Weight of Object (in air): 270 grams
  • Weight of Object (submerged in water): 170 grams
  • Density of Water: 1.0 g/cm³

  Calculation:

  • Apparent Loss of Weight (Mass) = 270 g – 170 g = 100 g
  • Specific Gravity = 270 g / 100 g = 2.7 (Unitless)

  Interpretation: The calculated specific gravity of 2.7 closely matches the known specific gravity of aluminum (around 2.7-2.8), suggesting the sample is indeed pure aluminum.

  Example 2: Investigating an Unknown Liquid

  A chemist needs to determine the specific gravity of an unknown liquid. They use a pycnometer (a flask designed to hold a precise volume) to measure the weight of the liquid.

  • Weight of Pycnometer filled with Water: 100 grams
  • Weight of Pycnometer filled with Unknown Liquid: 95 grams
  • Weight of Empty Pycnometer: 50 grams
  • Density of Water: 1.0 g/cm³

  Calculation:

  • Weight of Water = 100 g – 50 g = 50 g
  • Weight of Unknown Liquid = 95 g – 50 g = 45 g
  • Density of Water = 50 g / Volume of Pycnometer
  • Density of Unknown Liquid = 45 g / Volume of Pycnometer
  • Specific Gravity = Density of Unknown Liquid / Density of Water
  • SG = (45 g / Volume) / (50 g / Volume) = 45 g / 50 g = 0.9 (Unitless)

  Interpretation: The specific gravity of 0.9 indicates the unknown liquid is less dense than water. This could be consistent with various organic solvents or light oils.

  Note: This example demonstrates a slightly different method (comparing weights of equal volumes) but uses the same underlying principle of density ratios. The calculator focuses on the method using buoyancy (weight difference when submerged).

How to Use This Specific Gravity Calculator

1. Step 1: Measure Weight in Air
   Accurately weigh the object whose specific gravity you want to determine while it is completely in the air. Enter this value into the “Weight of Object (in air)” field. Ensure you use consistent units (e.g., grams, kilograms).
2. Step 2: Measure Weight Submerged
   Submerge the object completely in water. Ensure no air bubbles are trapped on its surface. Weigh the object while it is submerged. Enter this value into the “Weight of Object (submerged in water)” field. Use the same units as in Step 1.
3. Step 3: Enter Density of Water
   Input the density of the water you used. The standard value is approximately 1000 kg/m³ or 1.0 g/cm³. Ensure the units of this density value are consistent with the units used for weight (e.g., if weights are in grams, use g/cm³ for density).
4. Step 4: Calculate
   Click the “Calculate Specific Gravity” button.

Reading the Results:

• Primary Result (Specific Gravity): This is the main output, a unitless number representing the ratio of the object’s density to water’s density.
• Intermediate Values:
  • Apparent Loss of Weight: The difference between the weight in air and the weight submerged, indicating the buoyant force.
  • Volume of Object: The volume of water displaced by the object, calculated using the apparent loss of weight and the density of water.
  • Density of Object: The mass per unit volume of the substance, calculated using its weight in air and its volume.
• Data Table: Provides a clear summary of all input values and calculated results with their respective units.
• Visual Representation: The chart helps visualize the density of the object relative to the density of water.

Decision-Making Guidance:

• SG > 1: The object is denser than water and will sink.
• SG < 1: The object is less dense than water and will float.
• SG = 1: The object has the same density as water.
• The precise value helps in material identification and quality control. Comparing calculated SG to known values for materials is a common practice.

Key Factors That Affect Specific Gravity Results

While the calculation itself is straightforward, several external factors can influence the accuracy of your specific gravity measurements:

1. Temperature: The density of both the substance being measured and water changes with temperature. Water is densest at about 4°C (1000 kg/m³ or 1 g/cm³). At higher temperatures, water density decreases, which would affect the calculated specific gravity if not accounted for. Standard measurements often specify the temperature conditions.
2. Accuracy of Weighing Instruments: The precision of your scale is paramount. Even small errors in weighing the object in air or submerged will lead to inaccurate specific gravity calculations. Using a calibrated, sensitive balance is crucial.
3. Complete Submersion and No Trapped Air: For the calculation to be valid, the object must be fully submerged, and no air bubbles should be clinging to its surface. Air bubbles reduce the effective buoyant force, leading to an underestimation of the object’s true volume and thus an incorrect specific gravity.
4. Purity of the Substance: Impurities or variations in the composition of the material being tested will alter its density and, consequently, its specific gravity. This is often why SG is used as a quality control measure.
5. Units Consistency: Ensuring that all weight measurements (in air, submerged) are in the same units (e.g., grams) and that the density of water uses compatible units (e.g., g/cm³) is essential for correct calculations. Mismatched units will yield nonsensical results.
6. Pressure: While less significant for typical solids and liquids under normal conditions, extreme pressure variations can slightly affect the density of substances, particularly gases and highly compressible liquids. For most practical applications, temperature is a far more dominant factor.
7. Buoyancy of the Weighing Medium: Standard calculations assume weighing occurs in air. Air has a small buoyant effect. For extremely precise measurements, the buoyancy of air itself on the object might be considered, though this is rarely necessary for basic specific gravity determinations.

Frequently Asked Questions (FAQ)

• Q1: What is the difference between specific gravity and density?
  
  Density is an absolute measure of mass per unit volume (e.g., kg/m³ or g/cm³), while specific gravity is a dimensionless ratio comparing the density of a substance to the density of a reference substance (usually water).
• Q2: Does the unit of weight matter for specific gravity calculation?
  
  Yes, the units for “Weight in Air” and “Weight Submerged” must be identical (e.g., both in grams, both in kilograms). As long as they are consistent, the final specific gravity value will be unitless. The units of the “Density of Water” input must be compatible for intermediate calculations (like volume).
• Q3: Why is the weight submerged less than the weight in air?
  
  When an object is submerged in water, it experiences an upward buoyant force equal to the weight of the water it displaces. This force counteracts the object’s weight, making it appear lighter.
• Q4: Can I calculate the specific gravity of a gas?
  
  Yes, but the reference substance is typically air instead of water. The principle remains the same: comparing the density of the gas to the density of air under specific conditions.
• Q5: What is the specific gravity of pure water?
  
  By definition, the specific gravity of pure water at its maximum density (around 4°C) relative to itself is 1.0.
• Q6: My calculated specific gravity is less than 1. What does this mean?
  
  A specific gravity less than 1 indicates that the substance is less dense than water. Therefore, it will float on water. Examples include wood, oil, and many plastics.
• Q7: My calculated specific gravity is greater than 1. What does this mean?
  
  A specific gravity greater than 1 means the substance is denser than water. It will sink in water. Examples include rocks, metals like iron and lead, and sugar solutions.
• Q8: How does temperature affect specific gravity measurements?
  
  Temperature affects the density of both the substance and the reference liquid (water). Water’s density changes significantly with temperature, especially above 4°C. For accurate comparisons, measurements should ideally be taken at a standardized temperature (e.g., 20°C) or the temperature must be noted and accounted for.
• Q9: Can this calculator determine the volume or density of the object?
  
  Yes, the calculator computes and displays the object’s apparent loss of weight, its volume (based on the density of water provided), and its density. The primary result remains the dimensionless specific gravity.

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